Question 1115628

the standard equation of a circle is:

{{{(x-h)^2+(y-k)^2=r^2}}} where {{{h}}} and {{{k}}} are {{{x}}} and {{{y}}} coordinates of the center, and {{{r}}} is radius


given:
 the center is at ({{{-2}}},{{{-5}}}), so we have  {{{h=-2}}} and {{{k=-5}}}

and {{{r= sqrt(2) }}}

{{{(x-(-2))^2+(y-5)^2=(sqrt(2))^2}}}

{{{(x+2)^2+(y+5)^2=2}}}-> your equation