Question 1115590
{{{(x^2-4x)+(y^2+6y)-20=0}}}
{{{(x^2-4x+4)+(y^2+6y+36)-20=4+36}}}
{{{(x-2)^2+(y+6)^2=60}}}
Circle centered at ({{{2}}},{{{-6}}}) with a radius of {{{R=sqrt(60)=2sqrt(15)}}}