Question 1115458
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The sum of thrice a positive number and 4 less than the square of the number, when divided by 4 more than the
number, yields a quotient of 6.
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{{{(3x+(x^2-4))/(x+4)=6}}}
This should be uncomplicated to solve.  You are asked for the positive result.

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{{{x^2-4+3x=6(x+4)}}}
{{{x^2+3x-4=6x+24}}}
{{{x^2-3x-28=0}}}
{{{(x+4)(x-7)=0}}}


{{{highlight(x=7)}}}



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Also notice that the original equation is undefined for x at -4.