<PRE><B>Question 1115269</B>
Meisha has $25,000 that she wants to invest. 

She invests  x @12%, y @ 7%, and z @ 6% 

The account paying 12% is a higher-risk account, so she wants the
amount in that account to be half of the amount she has in the account paying 6% simple
x=(1/2)z or z =2x
 Investment
x + y + z = 25000
x+y+2x=25000
3x+y=25000......................(1)
If her annual interest is $1945, 
12%x+7%y+6%z=1945
12%x+7%y+6%(2x)=1945
12x+7y+12x=194500
24x+7y=194500....................(2)

Equation for total investment											
											
3	x	+	1	y	=	25000	.............1				
											
Equation for interest 											
24	x	+	7	y	=	194500	.............2				
Eliminate 	y										
multiply (1)by		7									
Multiply (2) by		-1									
21	x		7	y	=	175000					
-24	x		-7	y	=	-194500					
Add the two equations											
-3	x				=	-19500					
/	-3										
x	=	6500									
plug value of			x	in (1)							
3	x	+	1	y	=	25000					
19500		+	1	y	=	25000					
			1	y	=	5500					
				y	=	5500					
Ans	x	=	6500								
	y	=	5500								
	6500	@12%									
	5500	@ 7%
        13000   @ 6%
									
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