Question 1115269
 Meisha has $25,000 that she wants to invest. 
She invests it in accounts paying 12%, 7%, and 6% simple interest. 
The account paying 12% is a higher-risk account, so she wants the
amount in that account to be half of the amount she has in the account paying 6% simpleinterest. 
If her annual interest is $1945, how much is invested at each rate? 
Equations:
t + s + x = 25000
t = (1/2)x
12t + 7s + 6x = 194500
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Modify and rearrange to get:
t + s + x = 25000
t + 0 -0.5x = 0
12t+7s+6s = 194500
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Solve by any method you know to get:
t = 6500
s = 5500
x = 13000
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Cheers,
Stan H.
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