Question 1115212
{{{ 4^(3x) = 7^(x+1) }}}
3x*log(4) = (x+1)*log(7)
x*log(64) = x*log(7) + log(7)
x*log(64) - x*log(7) = log(7)
x*(log(64) - log(7)) = log(7)
x = log(7)/(log(64/7)
x =~ 0.87932