Question 1115173
<pre>
first number      3(2n+2-n)=3(n+2)
second number     2n+2
third number       n
</pre>

One single equation in variable n.
{{{3(n+2)+(2n+2)+n=32}}}

Solve and evaluate firstnumber and secondnumber.


The problem seems not to really benefit from using matrices.


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If really matrix is wanted, then first second third numbers can be x, y, z.
Description could be system of equations:
{{{system(x+y+z=32,x-3y+3z=0,y-2z=2)}}}


Corresponding starting matrix would be  
{{{matrix(3,4,
1,1,1,32,
1,-3,3,0,
0,1,-2,2)}}}