Question 1115170
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In all, there are 4 + 2 + 3 + 1 = 10 marbles.


In how many ways can you select 8 marbles of 10 ?  - In  {{{C[10]^8}}} = {{{(10*9)/(1*2)}}} = 45 ways.


How many of these combinations do not include the two green marbles ?  - Only one combination.



Therefore, the probability under the question is  {{{1/45}}}.
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