Question 1115105
(x^-1/3y^5/6)^3 / y^-1/2
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Do you mean
{{{(x^-1/3y^5/6)^3 / y^-1/2}}} ?
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Or
{{{(x^(-1/3)y^(5/6))^3 / y^(-1/2)}}} ?
= {{{(x^(-1)y^(5/2)) / y^(-1/2)}}}
= {{{(y^(5/2))^1 / (x*y^(-1/2))}}}
= {{{(y^(6/2))^1 / (x)}}}
= y^3/x
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The exponent 1's are just to make it more readable on the site.