Question 1115086
{{{Q=I*b^x}}}


{{{1=1b^0}}}


{{{1160=b^9}}}


{{{log((1160))=9*log((b))}}}


{{{log((b))=log((1160))/9}}}


{{{log(b)=0.3405}}}

{{{b=2.19}}}


{{{highlight(Q=2.19^x)}}}
x, time in years since 2001



(not the only possible arrangement)