Question 1115011
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Very 1-st day, 6:00 am after injection  200

     2-nd day, 6:00 am after injection  200 + 0.6*200

     3-rd day, 6:00 am after injection  200 + 0.6*200 + 0.6^2*200

     4-th day, 6:00 am after injection  200 + 0.6*200 + 0.6^2*200 + 0.6^3*200



Do you see the pattern ?


For a long time "after" (many days after) the accumulated amount at 6:00 am after injection = ( approximately equal but slightly less than )

 = the sum of the infinite geometric progression with the first term of 200 mg and the common ratio of  0.6 = 


= {{{200/(1-0.6)}}} = 200/0.4 = 500 mg.



The minimum accumulated level is the minutes BEFORE  6:00 am, before the current injection,  and it is equal to

   1 minute before 6:00 am of the 2-nd day 0.6*200 = 120 mg.

   1 minute before 6:00 am of the 3-rd day 0.6*200 + 0.6^2*200 = 192 mg.

   1 minute before 6:00 am of the 4-th day 0.6*200 + 0.6^2*200  + 0.6^3*200 = 235 mg.

   1 minute before 6:00 am of the 5-th day 0.6*200 + 0.6^2*200  + 0.6^3*200 + 0.6^3*200 = 278.4 mg.
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Having this model and the numbers, you are now in position to make your own conclusions.