Question 1115002
The mean change is 3.6 with sd 16.7. 
99% CI half interval is t(0.995, df=42)*16.7/sqrt(43)
t=2.70
half interval is 6.88
the interval is +3.6+/-6.88
(-3.28, 10.48)
0 is in the interval; therefore, one has to conclude there is no significant change with this particular test.