Question 1114988
Im having difficulty telling whether an x value is a solution for the equation. For example ln 2x = 8,x= e^8. Also just logrithms in general and would love help for these kinds of questions and others if you have the time. Thank you. 
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Looking at ln(2x) = 8
base = e
ln = exponent = 8
result = 2x
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Exponential form so you can solve for "x":
2x = e^8
x = (1/2)e^8
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Cheers,
Stan H.