<PRE><B>Question 1114960</B>
 I hope that someone can help me solve this problem: n=3; -5 and 4+3i are zeros; f(2)=273. Can you please help? 
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f(n) = a(n-3)(n+5)(n-(4+3i))
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f(2) = a(-1)(7)(-2-3i) = 273
a = -39/(-2-3i) = 39/(2+3i)
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Equation:
f(n) = [(39/(2+3i))(n-3)(n+5)(n-(4+3i)]
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Cheers,
Stan H.
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