Question 1114915
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{{{abs(x-1)^(x^2+3x)}}} = {{{abs(x-1)^(5-x)}}}  ====>  


x^2 + 3x = 5 - x  ====>


x^2 + 4x - 5 = 0


(x+5)*(x-1) = 0


The roots are  x= -5  and  x= 1.


Both the roots satisfy the original equation.


<U>Answer</U>.  The solutions are  x= -5  and  x= 1.
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