<PRE><B>Question 1114859</B>
 Use the function h(t)=-16t^2+v0t+s 
A projectile is launched from a building 256 feet tall. If the initial velocity of the projectile was 96 feet per second, how long will it take the projectile to land on the ground? 
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Equation:
0 = -16t^2+96t+256
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Divide thru by -16 to get:
t^2 - 6t - 16 = 0
(t-8)(t+2) = 0
Positive solution::
time = 8 seconds
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Cheers,
Stan H.
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