<PRE><B>Question 1114842</B>
In a recent presidential election, 611 voters were surveyed and 308 of them said that they voted for the candidate who won (based on data from the ICR Survey Research Group). Find a 99% confidence interval estimate of the percentage of voters who said that they voted for the candidate who won.
----
sample proportion:: 308/611 = 0.5041
ME = z*sqrt(pq/n) = 2.5758*sqrt[(308/611)*(303/611)/611] = 0.0521
----
99% CI: 0.5041-0.0521 &lt; p &lt; 0.5041+0.0521
--------------
Cheers,
Stan H.
-------</PRE>