Question 1114796
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You are given

p + q = n,

m = {{{1/p + 1/q}}} = {{{(q+p)/(pq)}}} = {{{n/pq)}}},   (  <<<---=== I replaced p+q in the numerator by n, since it is given !  )


which implies  pq = n/m.


Then  {{{(p-q)^2}}} = {{{(p+q)^2 - 4pq}}} = {{{n^2-4*(n/m)}}}.


<U>Answer</U>.  Then  {{{(p-q)^2}}} = {{{n^2-4*(n/m)}}}.
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Solved.