Question 1114755
.
<pre>
Let x be the amount invested at 5%, in dollars.

Then the amount invested at 7% is (x-760) dollars.


The annual income from the two amounts is

0.05*x + 0.07*(x-760)  dollars


Which gives you an equation

0.05*x + 0.07*(x-760) = 51.20   dollars.


Simplify and solve for x

0.05x + 0.07x - 0.07*760 = 51.20,

0.12x = 51.20 + 0.07*760 = 104.40 

x = {{{104.40/0.12}}} = 870.


<U>Answer</U>.  $870 was invested at 5%.  760 dollars less, or  870-760 = 110 dollars was invested at 7%.


<U>Check</U>.  0.05*870 + 0.07*110 = 51.20  dollars.    ! Correct ! 
</pre>

-----------------
It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.