Question 1114760
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<pre>
Let x be the amount invested at 3%, in dollars.

Then the rest, (2200-x) was invested at 5%.


The annual interest from the 3% account is  0.03*x 

The annual interest from the 5% account is 0.05*(2200-x).


The condition says

0.03*x = 0.05*(2200-x) - 46  dollars.


Simplify and solve for x:

0.03x = 110 - 0.05x - 46

0.03x + 0.05x = 110 - 46

0.08x = 64  ====>  x = {{{64/0.08}}} = {{{6400/6}}} = 800 dollars.


<U>Answer</U>.  $800 was invested at 3%.  The rest,  2200-800 = 1400 dollars was invested at 5%.


<U>Check</U>.   0.03*800 - 0.05*1400 = -46.    ! Correct !
</pre>

Solved.


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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.