Question 1114732
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Sunita has a coin collection of dimes, quarters, and silver dollars. 


The number of quarters is 5 less then three-fourths of the number of dimes.
q = (3/4)d - 5


The number of silver dollars is 7 more than five-eighths of the number of dimes.
s = (5/8)d+7


There are 116 coins in all.
s + q + d = 116


Substitute for "q" and "s"  and solve for "d"::

(5/8)d+7 + (3/4)d - 5 + d = 116
(5/8)d   + (6/8)d + d = 116 - 7 + 5


(19/8)d = 114

d = {{{(114*8)/19}}} = 48


Then  q = (3/4)d - 5 = (3/4)*48 - 5 = 36-5 = 31.

      s = (5/8)d+7   = (5/8)*48 + 7 = 30 + 7 = 37.


<U>Answer</U>.  48 dimes,  31 quarters  and  37 silver dollars.
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Solved.