Question 1114721
the duration of a heart operation is a normally distributed random variable with mean 160 minutes and standard deviation 22 minutes. What percentage of operations last longer than 176 minutes? 
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z(176) = (176-160)/22 = 16/22 = 8/11
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P(x > 176) = P(z > 8/11) = normalcdf(8/11,100) = 0.2335
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Cheers,
Stan H.
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