Question 1114631
{{{abs(v)=sqrt((dx/dt)^2+(dy/dt)^2)}}}
{{{dx/dt=10t+1}}}
{{{dy/dt=-8}}}
When {{{t=3}}},
{{{dx/dt=10(3)+1=30+1=31}}}
{{{dy/dt=-8}}}
So,
{{{abs(v)=sqrt((31)^2+(-8)^2)}}}
Work that out for the answer.