Question 1114534
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<pre>
Let r be the speed of the slower-moving car, in miles per hour.

Then the speed of the faster car is (r+10) mph.


The distance equation is


4r + 4*(r+10) = 456.


4r + 4r + 40 = 456

8r = 456-40 = 416  ====>  r = {{{416/8}}} = 52.


<U>Answer</U>.  The speed of the slower-moving car is 52 mph.
</pre>

Solved.


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