Question 1114515
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{{{3^(x+2)+2^(x+2)+2^x}}} = {{{2^(x+5)+3^x}}}  ====>


{{{3^(x+2) - 3^x}}} = {{{2^(x+5) - 2^(x+2) - 2^x}}}   ====>


{{{3^x*(3^2-1)}}} = {{{2^X*(2^5-2^2-1)}}}  ====>


{{{3^x*8}}} = {{{2^x*27}}}.   (*)


At this point, you can guess at least one root  x = 3.


Next, transforming (*) into


{{{(3/2)^x}}} = {{{27/8}}},


you can see that this root is unique: there are NO other roots.
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