Question 1114339
<pre>Since VYZ, VYX, and VVW are consecutive integers, these
additions of 1 must be true.

VYZ     VYX
<u> +1</u>     <u> +1</u>
VYX     VVW

From the addition on the left we see that Z+1=X for nothing was
carried, since digits V and Y stayed the same when 1 was added

From the addition on the right, 1 must be carried to the middle
column of digits; for otherwise, the middle V in VVW would have
been Y.  Since these are consecutive integers, and this
is the first time there was 1 to carry, X must be the 
largest digit X=4, and W=0. And since Z+1=X, Z=X-1=4-1=3. So the 
above two additions are now

         1
VY3     VY4
<u> +1</u>     <u> +1</u>
VY4     VV0

The only two digits that haven't been used are 1 and 2.
From the second addition we see from the middle column that V 
must be larger than Y, so Y=1 and V=2.  So the additions are

213     214
<u> +1</u>     <u> +1</u>
214     220

The question is:

what is the base 10 expression for the integer coded as XYZ?

"XYZ" = 25X+5Y+Z = 25(4)+5(1)+3 = 100+5+3 = 108.

Edwin</pre>