Question 1114237
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A parabola has intercepts of x = -2, x = 3, and y = -4.
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{{{y=a(x+2)(x-3)}}}
{{{a=y/((x+2))(x-3))}}}
Given point includes (0,-4).
{{{a=-4/(2*(-3))}}}

{{{a=-4/(-6)}}}

{{{a=2/3}}}


{{{highlight(y=(2/3)(x+2)(x-3))}}}


You can do the algebra & multiplication for the "standard" form.