Question 1114134
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The number of ways of arranging 10 balls, of which 4 are one color, some unknown number x are another color, and the remaining balls are all different colors, is<br>
{{{10!/(4!)(x!)}}}<br>
So
{{{(10*9*8*7*6*5)/(x!) = 6300}}}
{{{x! = (10*9*8*7*6*5)/(6300) = 24}}}
{{{x = 4}}}<br>
There are 4 green balls.