Question 1114110
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Note that {{{9/16 = (3/4)^2}}} and {{{64/27 = (4/3)^3}}}.<br>
To solve the equation, we want to make the fractions the same. So rewrite {{{(4/3)^3}}} as {{{(3/4)^(-3)}}}.<br>
Then<br>
{{{(9/16)^(2-x)=(64/27)^x}}}
{{{((3/4)^2)^(2-x) = (((3/4)^-3)^x))}}}
{{{(3/4)^(4-2x) = (3/4)^(-3x)}}}
{{{4-2x = -3x}}}
{{{x = -4}}}