Question 1114031
A jar of peanut butter contains 456 g with a standard deviation of 10.2 g. Find the probability that a jar contains less than 444 g. Assume a normal distribution.
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z(444) = (444-456)/10.2 = -1.1765
p(x < 444) = p(z < -1.765) = normalcdf(-100,-1.765) = 0.0388 = 3.88%
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Cheers,
Stan H.
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