Question 1114013
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The solution by  @josgatithmetic is incorrect.  Below find the correct version.


<pre>
A=10^((B-C)/D)*E*F



{{{A=10^((B-C)/D)*E*F}}}


{{{A/(EF) = 10^((B-C)/D)}}}


{{{log((A/(EF)))}}} = {{{(B-C)/D}}}


{{{B-C}}} = {{{D*log((A/EF)))}}}


B = {{{D*log((A/(EF)))+C)}}}
</pre>