Question 205740
{{{s(t)=t^3+2t^2}}} (Position function) 

{{{v(t)=3t^2+4t}}} (Instantaneous velocity at any time t)

{{{E=(1/2)*m*v^2=(1/2)(2.5)(3t^2+4t)^2}}} (Kinetic energy of particle) 

             ={{{(1/2)(2.5)(9t^4+24t^3+16t^2)}}}

             ={{{(1.2)(9t^4+24t^3+16t^2)}}}

             ={{{10.8t^4+28.8t^3+19.2t^2}}} (Answer)