Question 840522
The velocity of the object is given by {{{v(t)=-32t+96}}}


The maximum distance above the ground occurs when the velocity of the ball is 0.


-32t+96=0, therefore t=3. The object reaches its maximum height after 3 s.


a){{{ s(3)=(-16)(9)+288+120=264 ft}}} (Answer)


For b), the ball is at the top of the building at time t=0.


{{{s(0)=0+0+120=120 ft}}} (Answer)