Question 1113801
The sample mean is {{{xbar = 26.6}}}
The population mean is {{{mu = 26.2}}} (this is the greek letter mu). 
The sample standard deviation is {{{s = 5.3}}}. 
The sample size is {{{n = 16}}}


Using that info, we find the following:
{{{t = (xbar - mu)/(s/sqrt(n))}}}


{{{t = (26.6 - 26.2)/(5.3/sqrt(16))}}}


{{{t = (0.4)/(5.3/4)}}}


{{{t = (0.4)/(1.325)}}}


{{{t = 0.30188679245283}}} This value is approximate


{{{t = 0.30}}} This value is approximate


Rounded to two decimal places, the t value is approximately {{{t = 0.30}}}


Therefore, the answer is choice B