Question 1113778
 How do I find the missing angles and sides in this triangle? I was told to solve via using the Law of Sines and Cosines. 
Triangle: https://i.imgur.com/lhsjUel.png 
For my solution currently I have: 
Angle A = 49 degrees 
Angle B = 66 degrees
Angle C = 65 degrees 
side a = 18
side b = 22.7883
side c = 11 
I just want to make sure my answer is correct. 
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Law of Sines::
sin(C)/11 = sin(49)/18
sin(C) = (11/18)(sin(49) = 0.4612
C = arcsin(0.4612) = 27.47 degrees
The B = 180-(27.47+49) = 103.53 degrees
Use Law of Sines to find side AC which is opposite angle B.
Cheers,
Stan H.
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