Question 1113773
solve for x if [3 1 0
                2 x 1
                4 5 -2]  = 0
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<pre>

|3   1   0|
|2   x   1| = 0
|4   5  -2|
===============
|2   x   1|
|3   1   0| = 0
|4   5  -2|
=================
|x   2   1|
|1   3   0| = 0
|5   4  -2|
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</pre>
x*(-6-0) - 2*(-1-0) + 1*(4-15) = 0
-6x + 2 - 11 = 0
-6x = 9
x = -3/2
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the transposing is not necessary, but it gives just one term with x.