Question 91991
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<U>1.  &nbsp;&nbsp;Algebra solution</U>


<pre>
    The formula for the height of a freely falling body under gravity force, that students learn and use in their Algebra exercises is 


    H(t) = {{{-(gt^2)/2}}} + {{{ho}}},  


    where  g = 32 ft/s^2  and h0 is the initial height (in feet).


    In this case, h0 = 1400 ft, therefore the equation to find the time t is 


    H(t) = 0,   or  {{{(-32t^2)/2 + 1400}}} = 0,   which is equivalent to


    16*t^2 = 1400,   which implies  t = {{{sqrt(1400/16)}}} = 9.35 seconds.


    <U>Answer</U>.  9.35 seconds.
</pre>


<U>2.  &nbsp;&nbsp;Physics solution</U>


<pre>
    In school Physics course, the students learn the formula for the distance which a freely falling body travels 
    vertically down under the gravity force


    H(t) = {{{(gt^2)/2}}}.


    where the included parameters were all explained in the Algebra solution.


    To find time,  get from this formula  t = {{{sqrt((2H)/g))}}} = {{{sqrt((2*1400)/32)}}} = 9.35 seconds,

    and you get the same answer.
</pre>


These are two standard, simplest and straightforward methods of Algebra and Physics to solve the problem.


What the tutor @amalm proposes in his post, is never used, and I do not recommend you to take it seriously.



Only the person who doesn't know basics,  can propose this approach.