Question 1113737
What is (1+i)^12 in standard form using De Moivre's Theorem
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The result is the same by any method.
De Moivre's Theorem is the least work for this one.
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(1+i)^12 = (sqrt(2)cis(45))^12
= 2^6cis(540)
= 64cis(180)
= -64