Question 1113668
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ |N\ -\ 2.27|\ <\ 0.005]


However, an absolute value inequality is inappropriate for expressing an accuracy assumption because the actual assumption is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2.365\ \leq\ N\ <\ 2.375]


which properly expresses the rounding rules.  You cannot be inclusive of equality on one end while exclusive of equality on the other end with an absolute value inequality.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  


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