Question 100099
Let x=first
x+2=the second
x+4=the third
And x+6=fourth

Now we are told that these consecutive odd integers add up to 216. So:

x+x+2+x+4+x+6=216  start collecting like terms

4x+12=216  subtract 12 from both sides

4x+12-12=216-12 and this equals:

4x=204  divide both sides by 4
x=51----first integer

x+2=51+2=53 second integer

x+4=51+4=55 third integer

x+6=61+6=57 fourth integer

CK

51+53+55+57=216
216=216


Hope this helps----ptaylor