Question 1113600
A piece of ice is 3' * 10.5" * 10.5".  Specific gravity of ice is .92.

Determine:

A) Amount of water in the ice.
3 * .875 * .875 = 2.296875 cu. ft. (Volume of ice).

B) Weight of ice.
Weight (or mass) = Vol*density
Density of water = 62.372 pounds/cu ft
W = 62.372*2.296875*0.92
W =~ 131.8 pounds
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