Question 1113540
One can find the roots of this equation by using the quadratic formula 
x=(1/2a)(-b+/- sqrt(b^2-4ac), where a=K, b=-1, and c=1

The first way assumes K is the same as k
the first using the quadratic formula is x=(1/2k)(1+/- sqrt (1-4k))
the other is x=(1/k)(1+/- sqrt (1-4k))
The ratio is (1/2k)/(1/k) or 1/2, since the (1+/-sqrt (1-4k)) cancel

If the K is not the same as k
(1/2K)(1+/- sqrt (1-4k))/(1/k)(1+/- sqrt (1-4k))
and this ratio is (1/2K)/(1/k) as above, which is k/2K