Question 1113519
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{{{xy=1200}}}  the area (length times width) is 1200
{{{2x+2y = 150}}}  the perimeter (twice length plus twice width) is 150<br>
{{{x+y = 75}}}
{{{y = 75-x}}}
{{{x(75-x) = 1200}}}
{{{75x-x^2 = 1200}}}
{{{x^2-75x+1200 = 0}}}<br>
Solve the equation using the quadratic formula.  Because both equations are symmetric in the two variables, the two solutions to the quadratic equation will be the length and width of the rectangle.<br>
Answers: 51.9 and 23.1