Question 1113504


given:
a length of {{{L=4x+3}}} and 
a width of {{{W=x+37}}} 

if a perimeter of at least {{{P=400}}}, and we know that {{{P=2(L+W)}}}, substitute given values 

{{{400=2(4x+3+x+37)}}}....solve for {{{x}}}

{{{400/2=4x+3+x+37}}}

{{{200=5x+40}}}

{{{200-40=5x}}}

{{{160=5x}}}

{{{160/5=x}}}

{{{x=32}}}

now we can find {{{L=4x+3}}} and {{{W=x+37}}}

{{{L=4x+3}}}
{{{L=4*32+3}}}
{{{L=131}}}

{{{W=x+37}}}
{{{W=32+37}}}
{{{W=69}}}

check:

{{{P=2(L+W)}}}

{{{P=2(131+69)}}}
{{{P=2(200)}}}
{{{P=400}}}