Question 1113396
let y = the unknown number
:
{{{(2x)/(2x-3)}}} = {{{y/(8x^3-27)}}}
multiply both sides by (8x^3-27)
y = {{{(2x(8x^3-27))/(2x-3))}}}
we can factor
y = {{{(2x(2x-3)(4x^2+6x+9))/(2x-3))}}}
Cancel
y = {{{2x(4x^2+6x+9))}}}