Question 100027
let angle one equal x
Given: angle two equals 1/3 the first
angle two = x/3
Given: angle three equals 26 degrees more than the first
angle three = x+26
Known: the sum of all angles in a triangle equals 180 degrees

{{{angleOne+angleTwo+angleThree=180}}}
{{{x+x/3+x+26=180}}}
{{{2x+x/3+26=180}}}
{{{(6x)/3+x/3+26=180}}}
{{{7x/3+26=180}}}
{{{7x/3=180-26}}}
{{{7x/3=154}}}
{{{7x=(154)(3)}}}
{{{7x=462}}}
{{{x=66}}}
So the first angle equals 66 degrees
angle two = x/3 = 66/3 = 22 degrees
angle three = x+26 = 66+26 = 93 degrees
check sum of all angles equals 180
66+22+93=180