Question 1113218
Wind resistance or atmospheric drag tend to slow down moving objects.
 Atmospheric drag varies jointly as an objects surface area A and velocity v.
 If a car traveling at speed of 60 mph with a surface area of 34 ft^2 experiences a drag of 244.8 N ( Newton's),
:
I always thought the air resistance varied with the square of velocity, however we will just do this with the information given
find k
 A*v*k = drag
 34*60*k = 244.8
 2040k = 244.8
 k = 244.8/2040
 k = .12
:
how fast must a car with 48ft^2 of surface area travel in order to experience a drag force of 368.64 N ? 
.12*48*v = 368.64
5.76v = 368.64
v = 368.64/5.76
v = 64 mph