Question 99124
g^2+5g+4/5g+5/g^2+8g+16/g^2+g-12
{{{(cross(g+4)cross(g+1))/(5*cross(g+1))/(cross(g+4)(g+4))/((g+4)(g-3))}}}
{{{1/(5(x-3)(x+4)^2)}}}
you will never get another of these wrong if you remember that the top is on top and the rest are on the bottom times each other.
simple example: a/b/c/d=a/(b*c*d)
think of it this way: a*(1/b)*(1/c)*(1/d)=a/(bcd)
the next one is a piece of cake:
x^2+2x+1/x^2+13x+12 
{{{((x+1)cross(x+1))/((x+12)cross(x+1))=(x+1)/(x+12)}}}
Ed