Question 1113321
u=ln x; dv=x^(-1/2) dx; v=2x^(1/2)
du= (1/x) dx
uv- int vdu
This is 2 x^(1/2)* ln x-2int [1/sqrt (x)dx]; the integral is 2x^(1/2)
or 2 (sqrt(x)){ln x-2)