Question 1113186
If {{{f(0)=0}}}, then the numerator must equal zero.
{{{q-pe^(-(C)*(p+q)))=0}}}
{{{q=pe^(-(C)*(p+q)))}}}
{{{q/p=e^(-(C)*(p+q)))}}}
{{{ln(q/p)=-C*(p+q)}}}
{{{C=-ln(q/p)/(p+q)}}}
{{{C=ln(p/q)/(p+q)}}}
{{{highlight(C=(ln(p)-ln(q))/(p+q))}}}